UtilJsonParseJsonTValue(String) Method
Parses a JSON string and returns a DictionaryTKey, TValue
representing the JSON key-value pairs, where all the values are casted to the specified 'TValue' type.
Namespace: DevCase.Core.DataProcessing.JsonAssembly: DevCase.net48 (in DevCase.net48.dll) Version: 6.0.0.0 (6.0)
XMLNS for XAML: Not mapped to an xmlns.
public static Dictionary<string, TValue> ParseJson<TValue>(
string json
)
Public Shared Function ParseJson(Of TValue) (
json As String
) As Dictionary(Of String, TValue)
Dim json As String
Dim returnValue As Dictionary(Of String, TValue)
returnValue = UtilJson.ParseJson(json)
public:
generic<typename TValue>
static Dictionary<String^, TValue>^ ParseJson(
String^ json
)
static member ParseJson :
json : string -> Dictionary<string, 'TValue>
No code example is currently available or this language may not be supported.
- json String
-
The JSON string to parse.
- TValue
-
The type of the values in the dictionary.
DictionaryString,
TValue
A
DictionaryTKey, TValue representing the JSON key-value pairs.
This method uses the
JavaScriptSerializer class to deserialize the JSON string into a dictionary.
It handles the deserialization process and returns the deserialized object.
This is a code example.
No code example is currently available or this language may not be supported.
Dim json As String = "{
""name"": ""John Doe"",
""age"": 30,
""city"": ""New York""
}"
Dim dict As Dictionary(Of String, String) = ParseJson(Of String)(json)
For Each key As String In dict.Keys
Console.WriteLine($"Key: {key}, Value: {dict(key)}")
Next
No code example is currently available or this language may not be supported.
No code example is currently available or this language may not be supported.
No code example is currently available or this language may not be supported.
No code example is currently available or this language may not be supported.